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LeetCode 3070 | Count Submatrices with Top-Left Element and Sum Less Than k | Java | CodeByTushu

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LeetCode 3070 | Count Submatrices with Top-Left Element and Sum Less Than k | Java | CodeByTushu

Description: πŸš€ Welcome Back to CodeByTushu!

In today’s video, we solve LeetCode 3070 β€” Count Submatrices with Top-Left Element and Sum Less Than k using 2D Prefix Sum in Java.

The problem asks us to count all submatrices starting at the top-left cell (0, 0) whose total element sum is less than or equal to k. Every such submatrix is uniquely determined by its bottom-right corner (i, j). Consequently, computing the sum of any candidate submatrix translates directly to finding the 2D prefix sum of the grid up to cell (i, j).

Using the inclusion-exclusion principle, the prefix sum at (i, j) is calculated from the current cell plus the sum of the cell directly above, plus the cell to the left, minus the diagonally overlapping top-left cell. We accumulate these prefix sums directly in-place within the matrix to maintain strict O(1) auxiliary space, checking whether each evaluated sum is less than or equal to k in optimal O(m * n) overall runtime.

πŸ”₯ Problem Highlights

βœ… Unique submatrix characterization anchored at the origin (0, 0)
βœ… Standard 2D prefix sum computation via the inclusion-exclusion principle
βœ… Seamless in-place matrix updates achieving strict O(1) auxiliary memory
βœ… Integer overflow safety with maximum total sum bounded by 10^9
βœ… Optimal single-pass linear time complexity running in under 2 milliseconds
βœ… Clean, production-ready solution applicable across large matrix dimensions

⏱️ TIMESTAMPS

00:00 Intro & Daily Challenge Overview
01:11 Problem Understanding & Fixed Top-Left Geometry
03:01 Key Insights: 2D Prefix Sum & Inclusion-Exclusion
04:54 Algorithmic Strategy & 3-Step Implementation
06:21 Clean Java Solution Walkthrough Line by Line
07:50 Test Cases Walkthrough & Step-by-Step Simulation
09:35 Time Complexity Analysis (O(MΒ·N) - 5 ms)
10:27 Space Complexity Analysis (O(1) Auxiliary Space)
11:10 Outro & Resources

πŸ“‚ Problem Folder & Detailed Documentation:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/tree/main/solutions/March/18-March/3070-Count-Submatrices-with-Top-Left-Element-and-Sum-Less-Than-k

β˜• Java Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/18-March/3070-Count-Submatrices-with-Top-Left-Element-and-Sum-Less-Than-k/Solution.java

🐍 Python Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/18-March/3070-Count-Submatrices-with-Top-Left-Element-and-Sum-Less-Than-k/solution.py

⚑ C++ Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/18-March/3070-Count-Submatrices-with-Top-Left-Element-and-Sum-Less-Than-k/solution.cpp

🌐 JavaScript Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/18-March/3070-Count-Submatrices-with-Top-Left-Element-and-Sum-Less-Than-k/solution.js

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πŸ’¬ Question of the Day

What is the inclusion-exclusion recurrence relation to compute the 2D prefix sum P[i][j] from its neighbors?

1️⃣ P[i][j] = grid[i][j] + P[i - 1][j] + P[i][j - 1] - P[i - 1][j - 1]
2️⃣ P[i][j] = grid[i][j] + P[i - 1][j] + P[i][j - 1] + P[i - 1][j - 1]
3️⃣ P[i][j] = grid[i][j] + P[i - 1][j - 1]
4️⃣ P[i][j] = grid[i][j] - P[i - 1][j] - P[i][j - 1] + P[i - 1][j - 1]

#LeetCode3070 #LeetCode #CountSubmatricesWithTopLeftElementAndSumLessThanK #Java #JavaDSA #PrefixSum #Matrix #Array #DSA #CodingInterview #ProblemSolving #LeetCodeMedium #DailyLeetCode #JavaProgramming #CodeByTushu

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