LeetCode 2943 | Maximize Area of Square Hole in Grid | Java | Medium | Array | CodeByTushu
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In today’s video, we solve LeetCode 2943 — Maximize Area of Square Hole in Grid using Array and Greedy Sorting in Java.
We are given a grid composed of 1x1 cells bounded by horizontal and vertical bars, with certain internal bars eligible for removal. To form a contiguous gap of height or width L, any intermediate bars between the boundary lines must be completely removed without leaving an internal partition. This key observation implies that only contiguous sequences of consecutive bar indices can be removed to create a larger opening, meaning removing k consecutive bars creates an opening of size k + 1.
By sorting both the removable horizontal bars and vertical bars, we identify the length of the longest consecutive sequence in each dimension. The maximum continuous height gap is maxConsecutive(hBars) + 1, and the maximum continuous width gap is maxConsecutive(vBars) + 1. Because the hole must be a square, its maximum side length is the minimum of these two values, yielding an optimal square area of side^2 in O(H log H + V log V) time and O(1) auxiliary space.
🔥 Problem Highlights
✅ Observation on why only strictly consecutive bar removals enlarge a single gap
✅ Independent calculation of maximum horizontal height and vertical width
✅ Finding the longest contiguous consecutive sequence via array sorting
✅ Direct square side computation using min(maxHGap, maxVGap)
✅ Clean handling of small arrays and boundary configurations
✅ Optimal O(H log H + V log V) time and O(1) auxiliary space complexity
⏱️ TIMESTAMPS
00:00 Intro
01:02 Problem Understanding
02:21 Observation & Consecutive Removal Formula
03:40 Approach (Decoupled Dimensions & Sorting)
04:54 Code Explanation
06:02 Code Run & Dry Run
07:33 Time Complexity Analysis
08:18 Space Complexity Analysis
08:54 Outro & Summary
📂 Problem Folder & Detailed Documentation:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/tree/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid
☕ Java Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/Solution.java
🐍 Python Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/solution.py
⚡ C++ Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/solution.cpp
🌐 JavaScript Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/solution.js
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💬 Question of the Day
Why can removing non-consecutive bars never create a single contiguous gap larger than removing consecutive bars?
1️⃣ Non-consecutive bars cancel each other out
2️⃣ Any bar that is not removed acts as an internal dividing line, splitting the area into smaller holes
3️⃣ Boundary bars shift position when non-consecutive bars are chosen
4️⃣ Non-consecutive bars can only create rectangular holes, never square holes
#LeetCode2943 #LeetCode #MaximizeAreaOfSquareHoleInGrid #Java #JavaDSA #Array #Sorting #Greedy #DSA #CodingInterview #ProblemSolving #LeetCodeMedium #DailyLeetCode #JavaProgramming #CodeByTushu
👇 Comment the answer below! 🔥 Close description
In today’s video, we solve LeetCode 2943 — Maximize Area of Square Hole in Grid using Array and Greedy Sorting in Java.
We are given a grid composed of 1x1 cells bounded by horizontal and vertical bars, with certain internal bars eligible for removal. To form a contiguous gap of height or width L, any intermediate bars between the boundary lines must be completely removed without leaving an internal partition. This key observation implies that only contiguous sequences of consecutive bar indices can be removed to create a larger opening, meaning removing k consecutive bars creates an opening of size k + 1.
By sorting both the removable horizontal bars and vertical bars, we identify the length of the longest consecutive sequence in each dimension. The maximum continuous height gap is maxConsecutive(hBars) + 1, and the maximum continuous width gap is maxConsecutive(vBars) + 1. Because the hole must be a square, its maximum side length is the minimum of these two values, yielding an optimal square area of side^2 in O(H log H + V log V) time and O(1) auxiliary space.
🔥 Problem Highlights
✅ Observation on why only strictly consecutive bar removals enlarge a single gap
✅ Independent calculation of maximum horizontal height and vertical width
✅ Finding the longest contiguous consecutive sequence via array sorting
✅ Direct square side computation using min(maxHGap, maxVGap)
✅ Clean handling of small arrays and boundary configurations
✅ Optimal O(H log H + V log V) time and O(1) auxiliary space complexity
⏱️ TIMESTAMPS
00:00 Intro
01:02 Problem Understanding
02:21 Observation & Consecutive Removal Formula
03:40 Approach (Decoupled Dimensions & Sorting)
04:54 Code Explanation
06:02 Code Run & Dry Run
07:33 Time Complexity Analysis
08:18 Space Complexity Analysis
08:54 Outro & Summary
📂 Problem Folder & Detailed Documentation:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/tree/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid
☕ Java Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/Solution.java
🐍 Python Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/solution.py
⚡ C++ Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/solution.cpp
🌐 JavaScript Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/January/15-January/2943-Maximize-Area-of-Square-Hole-in-Grid/solution.js
🔗 LeetCode Source Code
📌 Admin type the link
🌐 All LeetCode Solutions
📌 https://codebytushu.com/Leetcode/
📱 Join CodeByTushu on WhatsApp
Get coding updates, LeetCode solutions, daily questions and more.
https://whatsapp.com/channel/0029Vb8k5mCDeON2Xwlkxe40
❤️ Donate
📌 https://codebytushu.com/Leetcode/donate.php
🔥 Perfect For
LeetCode Medium Problems
Java DSA Preparation
Array & Sorting Techniques
Greedy Interval Analysis
Grid & Matrix Optimization
Time Complexity Optimization
Coding Interview Preparation
Problem Solving
🌐 Follow CodeByTushu
▶️ YouTube: https://www.youtube.com/@codebytushu
📸 Instagram: https://instagram.com/codebytushu/
💼 LinkedIn: https://www.linkedin.com/company/codebytushu/
🌍 Website: https://codebytushu.com
🐙 GitHub: https://github.com/CodeByTushu
❤️ Don’t Forget To
👍 Like | 💬 Comment | 🔔 Subscribe
💬 Question of the Day
Why can removing non-consecutive bars never create a single contiguous gap larger than removing consecutive bars?
1️⃣ Non-consecutive bars cancel each other out
2️⃣ Any bar that is not removed acts as an internal dividing line, splitting the area into smaller holes
3️⃣ Boundary bars shift position when non-consecutive bars are chosen
4️⃣ Non-consecutive bars can only create rectangular holes, never square holes
#LeetCode2943 #LeetCode #MaximizeAreaOfSquareHoleInGrid #Java #JavaDSA #Array #Sorting #Greedy #DSA #CodingInterview #ProblemSolving #LeetCodeMedium #DailyLeetCode #JavaProgramming #CodeByTushu
👇 Comment the answer below! 🔥 Close description
