LeetCode 1009 | Complement of Base 10 Integer | Java | Easy | Bit Manipulation | CodeByTushu
Description: π Welcome Back to CodeByTushu!
In todayβs video, we solve LeetCode 1009 β Complement of Base 10 Integer using Bit Manipulation and Bit Smearing in Java.
The complement of an integer is obtained by flipping all 0s to 1s and all 1s to 0s in its binary representation without leading zeros. Unlike a standard bitwise NOT operation which inverts all 32 bits and produces a negative two's complement integer, this problem requires flipping only the significant bits from the highest set bit down to bit 0.
To flip only the significant bits, we construct an all-ones bitmask matching the length of the binary representation and XOR it with the original number. Using a constant-time bit-smearing technique, we propagate the highest set bit across all lower positions through five successive bitwise shifts and OR operations, handling the edge case of n = 0 directly in optimal O(1) time and O(1) auxiliary space.
π₯ Problem Highlights
β Bitwise NOT limitation vs significant bits complement
β Efficient bit-smearing propagation without loops
β Constructing an all-ones bitmask of exact significant length
β Handling edge case n = 0 returning 1
β O(1) time complexity with 5 fixed bitwise operations
β Auxiliary Space Complexity: O(1)
β±οΈ TIMESTAMPS
00:00 Intro & Daily Challenge Overview
01:31 Problem Understanding & Bit Flips vs Standard NOT
03:05 Key Bit Smearing Insights & MSB Propagation
05:06 Bit Smearing Algorithm & Bitwise XOR
06:20 Clean Java Solution Walkthrough Line by Line
07:17 Test Cases Walkthrough & Step-by-Step Simulation
08:51 Time Complexity Analysis (O(1) Time - 11 Instructions - 0 ms)
09:38 Space Complexity Analysis (O(1) Auxiliary Space - Single Register)
10:11 Outro & Resources
π Problem Folder & Detailed Documentation:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/tree/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer
β Java Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/Solution.java
π Python Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/solution.py
β‘ C++ Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/solution.cpp
π JavaScript Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/solution.js
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π₯ Perfect For
LeetCode Easy Problems
Java DSA Preparation
Bit Manipulation Patterns
Bit Smearing Techniques
Bitwise Masking
Time Complexity Optimization
Coding Interview Preparation
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π¬ Question of the Day
Why is a direct bitwise NOT (~n) insufficient for finding the complement of a positive base-10 integer in 32-bit representations?
1οΈβ£ It flips all leading zeros into ones, yielding a negative two's complement number
2οΈβ£ It causes an arithmetic overflow exception on odd numbers
3οΈβ£ It shifts all bits one position to the left instead of inverting them
4οΈβ£ It only flips the least significant bit
#LeetCode1009 #LeetCode #ComplementOfBase10Integer #Java #JavaDSA #BitManipulation #Math #DSA #CodingInterview #ProblemSolving #LeetCodeEasy #DailyLeetCode #JavaProgramming #CodeByTushu
π Comment the answer below! π₯Β Close description
In todayβs video, we solve LeetCode 1009 β Complement of Base 10 Integer using Bit Manipulation and Bit Smearing in Java.
The complement of an integer is obtained by flipping all 0s to 1s and all 1s to 0s in its binary representation without leading zeros. Unlike a standard bitwise NOT operation which inverts all 32 bits and produces a negative two's complement integer, this problem requires flipping only the significant bits from the highest set bit down to bit 0.
To flip only the significant bits, we construct an all-ones bitmask matching the length of the binary representation and XOR it with the original number. Using a constant-time bit-smearing technique, we propagate the highest set bit across all lower positions through five successive bitwise shifts and OR operations, handling the edge case of n = 0 directly in optimal O(1) time and O(1) auxiliary space.
π₯ Problem Highlights
β Bitwise NOT limitation vs significant bits complement
β Efficient bit-smearing propagation without loops
β Constructing an all-ones bitmask of exact significant length
β Handling edge case n = 0 returning 1
β O(1) time complexity with 5 fixed bitwise operations
β Auxiliary Space Complexity: O(1)
β±οΈ TIMESTAMPS
00:00 Intro & Daily Challenge Overview
01:31 Problem Understanding & Bit Flips vs Standard NOT
03:05 Key Bit Smearing Insights & MSB Propagation
05:06 Bit Smearing Algorithm & Bitwise XOR
06:20 Clean Java Solution Walkthrough Line by Line
07:17 Test Cases Walkthrough & Step-by-Step Simulation
08:51 Time Complexity Analysis (O(1) Time - 11 Instructions - 0 ms)
09:38 Space Complexity Analysis (O(1) Auxiliary Space - Single Register)
10:11 Outro & Resources
π Problem Folder & Detailed Documentation:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/tree/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer
β Java Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/Solution.java
π Python Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/solution.py
β‘ C++ Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/solution.cpp
π JavaScript Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/11-March/1009-Complement-of-Base-10-Integer/solution.js
π LeetCode Source Code
π Admin type the link
π All LeetCode Solutions
π https://codebytushu.com/Leetcode/
π± Join CodeByTushu on WhatsApp
Get coding updates, LeetCode solutions, daily questions and more.
https://whatsapp.com/channel/0029Vb8k5mCDeON2Xwlkxe40
β€οΈ Donate
π https://codebytushu.com/Leetcode/donate.php
π₯ Perfect For
LeetCode Easy Problems
Java DSA Preparation
Bit Manipulation Patterns
Bit Smearing Techniques
Bitwise Masking
Time Complexity Optimization
Coding Interview Preparation
Problem Solving
π Follow CodeByTushu
βΆοΈ YouTube: https://www.youtube.com/@codebytushu
πΈ Instagram: https://instagram.com/codebytushu/
πΌ LinkedIn: https://www.linkedin.com/company/codebytushu/
π Website: https://codebytushu.com
π GitHub: https://github.com/CodeByTushu
β€οΈ Donβt Forget To
π Like | π¬ Comment | π Subscribe
π¬ Question of the Day
Why is a direct bitwise NOT (~n) insufficient for finding the complement of a positive base-10 integer in 32-bit representations?
1οΈβ£ It flips all leading zeros into ones, yielding a negative two's complement number
2οΈβ£ It causes an arithmetic overflow exception on odd numbers
3οΈβ£ It shifts all bits one position to the left instead of inverting them
4οΈβ£ It only flips the least significant bit
#LeetCode1009 #LeetCode #ComplementOfBase10Integer #Java #JavaDSA #BitManipulation #Math #DSA #CodingInterview #ProblemSolving #LeetCodeEasy #DailyLeetCode #JavaProgramming #CodeByTushu
π Comment the answer below! π₯Β Close description




