LeetCode 1886 | Determine Whether Matrix Can Be Obtained By Rotation | Java | Easy | CodeByTushu
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In today’s video, we solve LeetCode 1886 — Determine Whether Matrix Can Be Obtained By Rotation using Matrix Simulation and Coordinate Transformations in Java.
We are given two n x n binary matrices, mat and target. Our goal is to determine if we can make mat equal to target by rotating mat in 90-degree increments. Since rotating a 2D matrix four times returns it to its original orientation, there are exactly four candidate rotations to verify: 0, 90, 180, and 270 degrees clockwise.
Instead of creating intermediate matrices and performing costly multiple in-place transformations, we track four boolean flags for each degree of rotation simultaneously. In a single pass through the n x n matrix, we compare mat(i, j) with the corresponding rotated target coordinate. If any of the four flags remains true throughout the entire matrix traversal, a valid rotation exists, giving an optimal O(n^2) runtime and O(1) auxiliary space.
🔥 Problem Highlights
✅ Complete Rotation Coverage: Evaluates all four valid rotational orientations (0°, 90°, 180°, 270°)
✅ Single-Pass Efficiency: Checks all four rotation candidates concurrently without multiple loops
✅ Direct Coordinate Transformations: Maps cell (i, j) to (j, n - 1 - i), (n - 1 - i, n - 1 - j), and (n - 1 - j, i)
✅ Zero Additional Memory: Avoids allocating new 2D grid buffers or copying memory
✅ Edge Cases Handled: Matrices already identical at 0°, symmetric configurations, and small n = 1 matrices
✅ Optimal Complexity: O(n^2) time complexity and O(1) auxiliary space
⏱️ TIMESTAMPS
00:00 Intro & Daily Challenge Overview
01:20 Problem Understanding & 90-Degree Rotations
03:14 Key Insights: The 4 Coordinate Mapping Formulas
05:13 Algorithmic Strategy & Single-Pass Implementation
06:48 Clean Java Solution Walkthrough Line by Line
08:23 Test Cases Walkthrough & Step-by-Step Simulation
10:55 Time Complexity Analysis (O(N²) - 0 ms, Beats 100%)
11:57 Space Complexity Analysis (O(1) Auxiliary Space)
12:46 Outro & Resources
📂 Problem Folder & Detailed Documentation:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/tree/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation
☕ Java Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/Solution.java
🐍 Python Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/solution.py
⚡ C++ Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/solution.cpp
🌐 JavaScript Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/solution.js
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💬 Question of the Day
When rotating an n x n matrix 90 degrees clockwise, what is the new position of the element originally located at (i, j)?
1️⃣ (j, n - 1 - i)
2️⃣ (n - 1 - j, i)
3️⃣ (n - 1 - i, n - 1 - j)
4️⃣ (j, i)
#LeetCode1886 #LeetCode #DetermineWhetherMatrixCanBeObtainedByRotation #Java #JavaDSA #Matrix #Simulation #Array #DSA #CodingInterview #ProblemSolving #LeetCodeEasy #DailyLeetCode #JavaProgramming #CodeByTushu
👇 Comment the answer below! 🔥 Close description
In today’s video, we solve LeetCode 1886 — Determine Whether Matrix Can Be Obtained By Rotation using Matrix Simulation and Coordinate Transformations in Java.
We are given two n x n binary matrices, mat and target. Our goal is to determine if we can make mat equal to target by rotating mat in 90-degree increments. Since rotating a 2D matrix four times returns it to its original orientation, there are exactly four candidate rotations to verify: 0, 90, 180, and 270 degrees clockwise.
Instead of creating intermediate matrices and performing costly multiple in-place transformations, we track four boolean flags for each degree of rotation simultaneously. In a single pass through the n x n matrix, we compare mat(i, j) with the corresponding rotated target coordinate. If any of the four flags remains true throughout the entire matrix traversal, a valid rotation exists, giving an optimal O(n^2) runtime and O(1) auxiliary space.
🔥 Problem Highlights
✅ Complete Rotation Coverage: Evaluates all four valid rotational orientations (0°, 90°, 180°, 270°)
✅ Single-Pass Efficiency: Checks all four rotation candidates concurrently without multiple loops
✅ Direct Coordinate Transformations: Maps cell (i, j) to (j, n - 1 - i), (n - 1 - i, n - 1 - j), and (n - 1 - j, i)
✅ Zero Additional Memory: Avoids allocating new 2D grid buffers or copying memory
✅ Edge Cases Handled: Matrices already identical at 0°, symmetric configurations, and small n = 1 matrices
✅ Optimal Complexity: O(n^2) time complexity and O(1) auxiliary space
⏱️ TIMESTAMPS
00:00 Intro & Daily Challenge Overview
01:20 Problem Understanding & 90-Degree Rotations
03:14 Key Insights: The 4 Coordinate Mapping Formulas
05:13 Algorithmic Strategy & Single-Pass Implementation
06:48 Clean Java Solution Walkthrough Line by Line
08:23 Test Cases Walkthrough & Step-by-Step Simulation
10:55 Time Complexity Analysis (O(N²) - 0 ms, Beats 100%)
11:57 Space Complexity Analysis (O(1) Auxiliary Space)
12:46 Outro & Resources
📂 Problem Folder & Detailed Documentation:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/tree/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation
☕ Java Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/Solution.java
🐍 Python Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/solution.py
⚡ C++ Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/solution.cpp
🌐 JavaScript Solution:
https://github.com/CodeByTushu/CodeByTushu-LeetCode-Solutions/blob/main/solutions/March/22-March/1886-Determine-Whether-Matrix-Can-Be-Obtained-By-Rotation/solution.js
🔗 LeetCode Source Code
📌 Admin type the link
🌐 All LeetCode Solutions
📌 https://codebytushu.com/Leetcode/
📱 Join CodeByTushu on WhatsApp
Get coding updates, LeetCode solutions, daily questions and more.
https://whatsapp.com/channel/0029Vb8k5mCDeON2Xwlkxe40
❤️ Donate
📌 https://codebytushu.com/Leetcode/donate.php
🔥 Perfect For
LeetCode Easy Problems
Java DSA Preparation
Matrix Coordinate Geometry
Simulation Algorithms
In-Place Matrix Manipulations
Time Complexity Optimization
Coding Interview Preparation
Problem Solving
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▶️ YouTube: https://www.youtube.com/@codebytushu
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🐙 GitHub: https://github.com/CodeByTushu
❤️ Don’t Forget To
👍 Like | 💬 Comment | 🔔 Subscribe
💬 Question of the Day
When rotating an n x n matrix 90 degrees clockwise, what is the new position of the element originally located at (i, j)?
1️⃣ (j, n - 1 - i)
2️⃣ (n - 1 - j, i)
3️⃣ (n - 1 - i, n - 1 - j)
4️⃣ (j, i)
#LeetCode1886 #LeetCode #DetermineWhetherMatrixCanBeObtainedByRotation #Java #JavaDSA #Matrix #Simulation #Array #DSA #CodingInterview #ProblemSolving #LeetCodeEasy #DailyLeetCode #JavaProgramming #CodeByTushu
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