LeetCode 4084: Last Visited Cell in a Directional Grid | Java Solution | Medium
Description: In this video, we solve LeetCode 4084 – Last Visited Cell in a Directional Grid using Java! 🚀
We’ll understand the problem, simulate movement in a 2D grid, track visited cells, and determine the last visited position before the process stops.
📌 **What you'll learn:**
- How to solve grid simulation problems
- How to navigate a 2D matrix using L, R, U, and D
- How to detect revisited cells using a visited matrix
- How to implement the solution using an iterative approach
- Time and space complexity analysis
💡 **Approach:** Start at cell (0, 0), follow the direction at each cell, and stop when the next move goes outside the grid or reaches an already visited cell.
**Time Complexity:** O(m × n)
**Space Complexity:** O(m × n)
This problem is great practice for Java coding interviews and LeetCode problem-solving.
If you found this video helpful, like, share, and subscribe to **Cakot Coding** for more Java, DSA, and coding interview solutions!
#LeetCode #Java #DSA #CodingInterview #LeetCodeSolutions
LeetCode 4084, Last Visited Cell in a Directional Grid, LeetCode Java solution, LeetCode Medium, Java DSA, Data Structures and Algorithms, grid simulation, 2D array Java, matrix traversal, visited matrix, coding interview questions, LeetCode problems, Java programming, DSA interview preparation, algorithm practice, Cakot Coding Close description
We’ll understand the problem, simulate movement in a 2D grid, track visited cells, and determine the last visited position before the process stops.
📌 **What you'll learn:**
- How to solve grid simulation problems
- How to navigate a 2D matrix using L, R, U, and D
- How to detect revisited cells using a visited matrix
- How to implement the solution using an iterative approach
- Time and space complexity analysis
💡 **Approach:** Start at cell (0, 0), follow the direction at each cell, and stop when the next move goes outside the grid or reaches an already visited cell.
**Time Complexity:** O(m × n)
**Space Complexity:** O(m × n)
This problem is great practice for Java coding interviews and LeetCode problem-solving.
If you found this video helpful, like, share, and subscribe to **Cakot Coding** for more Java, DSA, and coding interview solutions!
#LeetCode #Java #DSA #CodingInterview #LeetCodeSolutions
LeetCode 4084, Last Visited Cell in a Directional Grid, LeetCode Java solution, LeetCode Medium, Java DSA, Data Structures and Algorithms, grid simulation, 2D array Java, matrix traversal, visited matrix, coding interview questions, LeetCode problems, Java programming, DSA interview preparation, algorithm practice, Cakot Coding Close description
